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QUESTION IMAGE

below are wing flaps - per - second for a sample of amethyst wood - sta…

Question

below are wing flaps - per - second for a sample of amethyst wood - star hummingbirds. 79.5, 79.8, 83.9, 75.7, 79.2, 80.0, 76.4, 79.3, 76.5, 79.8, 78.2, 81.3, 78.3, 77.8, 81.9, 79.4, 79.6, 81.9, 81.5, 76.8, 79.6, 86.3, 81.0, 83.4, 79.3. enter the five - number summary below. do not round any answers in this problem.

Explanation:

Step1: Sort the data

[75.7, 76.4, 76.5, 76.8, 77.8, 78.2, 78.3, 79.2, 79.3, 79.3, 79.4, 79.5, 79.6, 79.6, 79.8, 79.8, 80.0, 81.0, 81.3, 81.5, 81.9, 81.9, 83.4, 83.9, 86.3]

Step2: Find the minimum

The minimum value is 75.7.

Step3: Calculate the position of Q1

There are $n = 25$ data - points. The position of $Q1$ is $i=\frac{n + 1}{4}=\frac{25+1}{4}=6.5$. So, $Q1=\frac{78.2 + 78.3}{2}=78.25$.

Step4: Calculate the position of Q2 (median)

The position of $Q2$ is $i=\frac{n + 1}{2}=\frac{25+1}{2}=13$. So, $Q2 = 79.5$.

Step5: Calculate the position of Q3

The position of $Q3$ is $i=\frac{3(n + 1)}{4}=\frac{3\times(25 + 1)}{4}=19.5$. So, $Q3=\frac{81.3+81.5}{2}=81.4$.

Step6: Find the maximum

The maximum value is 86.3.

Answer:

MinimumQ1Q2Q3Maximum