Question

boyles law states that the volume of a gas varies inversely with applied pressure. suppose the pressure on 60 cubic meters of gas is raised from 1 atmosphere to 3 atmospheres. what new volume does the gas occupy? ? cubic meters

Explanation:

Step1: Recall Boyle's law formula

$P_1V_1 = P_2V_2$

Step2: Identify given values

$P_1 = 1$ atm, $V_1=60$ m³, $P_2 = 3$ atm

Step3: Solve for $V_2$

$V_2=\frac{P_1V_1}{P_2}=\frac{1\times60}{3}$
$V_2 = 20$ m³

Answer:

20