Question

brik has $1\frac{3}{8}$ ounces of salt. jayla has $\frac{3}{4}$ of the amount of salt that brik has. how much salt does jayla have?
$\frac{3}{4} \times 1\frac{3}{8} = \frac{3}{4} \times \frac{\boldsymbol{\square}}{8}$
$= \frac{\boldsymbol{\square}}{\boldsymbol{\square}}$
$= \boldsymbol{\square} \frac{\boldsymbol{\square}}{\boldsymbol{\square}}$

Explanation:

Step 1: Convert mixed number to improper fraction

The mixed number \(1\frac{3}{8}\) can be converted to an improper fraction. To do this, multiply the whole number (1) by the denominator (8) and add the numerator (3). So, \(1\times8 + 3=11\). Thus, \(1\frac{3}{8}=\frac{11}{8}\).

Step 2: Multiply the fractions

Now we have \(\frac{3}{4}\times\frac{11}{8}\). Multiply the numerators together and the denominators together: \(3\times11 = 33\) and \(4\times8 = 32\). So, \(\frac{3}{4}\times\frac{11}{8}=\frac{33}{32}\).

Step 3: Convert improper fraction to mixed number (if needed)

To convert \(\frac{33}{32}\) to a mixed number, divide 33 by 32. 32 goes into 33 once with a remainder of 1. So, \(\frac{33}{32}=1\frac{1}{32}\).

Filling in the blanks:

• The first blue box (for the numerator of the improper fraction) is 11.
• Then, \(\frac{3}{4}\times\frac{11}{8}=\frac{3\times11}{4\times8}=\frac{33}{32}\), so the next two boxes are 33 and 32.
• Finally, converting \(\frac{33}{32}\) to a mixed number gives \(1\frac{1}{32}\), so the last two boxes are 1 and \(\frac{1}{32}\) (or the numerator 1 and denominator 32 for the fraction part).

Answer:

First blue box: 11; Then \(\frac{33}{32}\) (so numerator 33, denominator 32); Finally \(1\frac{1}{32}\) (whole number 1, fraction numerator 1, fraction denominator 32)