Question

1. calculate the kinetic energy of a 5.2-kg object moving at 2.4 m/s.

Explanation:

Step1: Recall the kinetic energy formula

The formula for kinetic energy (\(KE\)) is \(KE = \frac{1}{2}mv^{2}\), where \(m\) is the mass of the object and \(v\) is its velocity.

Step2: Identify the given values

We are given that the mass \(m = 5.2\space kg\) and the velocity \(v = 2.4\space m/s\).

Step3: Substitute the values into the formula

First, calculate \(v^{2}\): \(v^{2}=(2.4)^{2}=5.76\space m^{2}/s^{2}\)
Then, substitute \(m\) and \(v^{2}\) into the kinetic energy formula:
\(KE=\frac{1}{2}\times5.2\times5.76\)

Step4: Perform the calculation

First, calculate \(\frac{1}{2}\times5.2 = 2.6\)
Then, multiply \(2.6\) by \(5.76\): \(2.6\times5.76 = 14.976\space J\)

Answer:

The kinetic energy of the object is \(14.976\space J\) (or approximately \(15.0\space J\) if rounded to three significant figures).