Question

1. calculate the net force on the rope.
2. calculate the net force to determine which team will win the tug of war.
3. michael and andrew are pushing a desk across the room. to be funny, michael decides to push against andrew instead of with him. michael can push with a force of 30 n. andrew can only push with a force of 28 n. in which direction will the desk move?
4. greg, matt, and stephen work together to hold the door shut to keep out the zombies. greg pushes with a force of 15 n, matt with 12 n, and stephen with 22 n. what is their net force on the door?
5. calculate the net force acting on the box below.

Explanation:

Step1: Define net - force concept

Net force is the vector sum of all forces acting on an object. Forces in opposite directions subtract, and forces in the same direction add.

Step2: Solve problem 6

The two forces on the rope are 30 N in opposite directions. Net force $F_{net}=30 - 30=0$ N.

Step3: Solve problem 7

For the left - hand team, the total force $F_{left}=38 + 15+40 = 93$ N. For the right - hand team, the total force $F_{right}=35 + 20+5 = 60$ N. Net force $F_{net}=93 - 60 = 33$ N. The left - hand team will win.

Step4: Solve problem 8

Michael's force $F_M = 30$ N and Andrew's force $F_A=28$ N. Since Michael's force is larger and in the opposite direction of Andrew's, the desk will move in Michael's direction.

Step5: Solve problem 9

Greg, Matt, and Stephen are pushing in the same direction. Net force $F_{net}=15 + 12+22=49$ N.

Step6: Solve problem 10

In the horizontal direction, the total force to the right $F_{right}=6 + 7+8 = 21$ N, and the total force to the left $F_{left}=5 + 5 = 10$ N. In the vertical direction, the total force up $F_{up}=2$ N and the total force down $F_{down}=2$ N. The vertical net force $F_{net - v}=2 - 2 = 0$ N. The horizontal net force $F_{net - h}=21 - 10 = 11$ N. The net force on the box is 11 N to the right.

Answer:

1. 0 N
2. The left - hand team will win with a net force of 33 N.
3. In Michael's direction.
4. 49 N
5. 11 N to the right.