Question

1. calculate the width of a 80\ tv if the tv has an aspect ratio of 21:9.○ 34.3\○ 56\○ 87\○ 73.5\

Explanation:

Step1: Define variables for dimensions

Let width = $9x$, height = $21x$. TV size is diagonal: $80''$.

Step2: Apply Pythagorean theorem

$$(9x)^2 + (21x)^2 = 80^2$$
$$81x^2 + 441x^2 = 6400$$
$$522x^2 = 6400$$

Step3: Solve for $x$

$$x^2 = \frac{6400}{522}$$
$$x = \sqrt{\frac{6400}{522}} \approx \sqrt{12.2605} \approx 3.5015$$

Step4: Calculate width

Width = $9x \approx 9 \times 3.5015$

Answer:

A. 34.3"