Question

cameron, arthur, and jamie are playing soccer. their locations are recorded by a motion - tracking system. the grid shows distances in meters. arthur is about meters away from camer (round to the nearest whole number as need) click the icon to view the soccer field. soccer field

Explanation:

Step1: Identify coordinates

Assume Cameron's position as $(x_1,y_1)$ and Arthur's position as $(x_2,y_2)$. From the grid, if we consider the grid - based coordinates (assuming the bottom - left as the origin), count the horizontal and vertical distances. Let's say Cameron is at about $(50,30)$ and Arthur is at about $(30,50)$.

Step2: Apply distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Substitute $x_1 = 50,y_1 = 30,x_2 = 30,y_2 = 50$ into the formula:
\[

$$\begin{align*} d&=\sqrt{(30 - 50)^2+(50 - 30)^2}\\ &=\sqrt{(- 20)^2+20^2}\\ &=\sqrt{400 + 400}\\ &=\sqrt{800}\\ &\approx28.28 \end{align*}$$

\]

Answer:

28 (rounded to the nearest whole number)