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if ce = 3s + 14 and cg = 8s - 1, find ce in parallelogram defg.

Question

if ce = 3s + 14 and cg = 8s - 1, find ce in parallelogram defg.

Explanation:

Step1: Set segments equal (diag bisect)

$CE = CG$
$3s + 14 = 8s - 1$

Step2: Solve for s

$14 + 1 = 8s - 3s$
$15 = 5s$
$s = \frac{15}{5} = 3$

Step3: Substitute s into CE

$CE = 3(3) + 14$
$CE = 9 + 14$

Answer:

23