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in a certain study, the chances of encountering a car crash on the road…

Question

in a certain study, the chances of encountering a car crash on the road are stated as 1 in 16. express the indicated degree of likelihood as a probability value between 0 and 1 inclusive. the probability is \boxed{}. (round to three decimal places as needed.)

Explanation:

Step1: Understand the probability

The phrase "1 in 16" means the number of favorable outcomes (encountering a car crash) is 1, and the total number of possible outcomes is 16. So the probability \( P \) is calculated as the number of favorable outcomes divided by the total number of outcomes.
\( P=\frac{1}{16} \)

Step2: Calculate the decimal value

We divide 1 by 16. \( 1\div16 = 0.0625 \)

Step3: Round to three decimal places

Rounding 0.0625 to three decimal places, we look at the fourth decimal place which is 5. When the digit to the right of the place we are rounding to (third decimal place here) is 5 or more, we round up the third decimal place. So 0.0625 rounded to three decimal places is 0.063.

Answer:

0.063