Question

challenge suppose you have a bag with 20 letter tiles in it and 3 of the tiles are the letter b. if you pick a letter tile at random from the b b is \\(\frac{3}{20}\\). suppose another bag has 300 letter tiles in it and 216 of the tiles are the letter b. write the probability of picking a tile that is the letter b as a fraction and as a percent. from which bag are you more likely to pick a tile that is the letter b?

p(b) as a fraction is \\(\frac{18}{25}\\).
(simplify your answer.)
p(b) as a percent is 72 %.
you are more likely to pick a tile that is the letter b from the bag with dropdown tiles in it.

Explanation:

Step1: Calculate probability for second bag

Probability = favorable/total = $\frac{216}{300} = \frac{18}{25}$

Step2: Convert fraction to percent

$\frac{18}{25} \times 100 = 72\%$

Step3: Compare probabilities

First bag: $\frac{3}{20}=15\%$ < 72%, so second bag (300 ties) is more likely.

Answer:

$\frac{18}{25}$, 72%, 300