Question

check your understanding of this lesson. solve the equation for x. \\(\frac{x}{a} - 5 = b\\) \\(\circ\\) \\(x = ab + 5\\) \\(\circ\\) \\(x = a + b + 5\\) \\(\circ\\) \\(x = 5ab\\) \\(\circ\\) \\(x = a(b + 5)\\) solve the equation for x. \\(2x - y = 18\\) blank show hint

Explanation:

First Sub - Question (Solving \(\frac{x}{a}-5 = b\) for \(x\))

Step1: Isolate the term with \(x\)

Add 5 to both sides of the equation \(\frac{x}{a}-5 = b\) to get \(\frac{x}{a}=b + 5\).

Step2: Solve for \(x\)

Multiply both sides of the equation \(\frac{x}{a}=b + 5\) by \(a\) (assuming \(a
eq0\)). We have \(x=a(b + 5)\).

Step1: Isolate the term with \(x\)

Add \(y\) to both sides of the equation \(2x - y=18\). This gives \(2x=18 + y\).

Step2: Solve for \(x\)

Divide both sides of the equation \(2x=18 + y\) by 2. So \(x=\frac{18 + y}{2}\) or \(x=\frac{y + 18}{2}\) (which can also be written as \(x = 9+\frac{y}{2}\)).

Answer:

D. \(x = a(b + 5)\)

Second Sub - Question (Solving \(2x-y=18\) for \(x\))