Question

1. choose the answer.

use gay-lussacs law to solve for the final celsius temperature.
$p_1 = 2.30\\ \text{l atm}$
$t_1 = 40.0\\ ^\circ\text{c}$
$p_2 = 6.50\\ \text{l atm}$
$t_2 = ?$
$685\\ ^\circ\text{c}$
$612\\ ^\circ\text{c}$
$113\\ ^\circ\text{c}$

Explanation:

Step1: Convert temp to Kelvin

$T_1 = 40.0 + 273.15 = 313.15\ \text{K}$

Step2: Apply Gay-Lussac's Law

Gay-Lussac's Law: $\frac{P_1}{T_1} = \frac{P_2}{T_2}$, rearrange to $T_2 = \frac{P_2 \times T_1}{P_1}$
Substitute values: $T_2 = \frac{6.50\ \text{atm} \times 313.15\ \text{K}}{2.30\ \text{atm}}$

Step3: Calculate Kelvin temp

$T_2 = \frac{6.50 \times 313.15}{2.30} \approx 885.15\ \text{K}$

Step4: Convert back to Celsius

$T_2 = 885.15 - 273.15 = 612\ ^\circ\text{C}$

Answer:

612 °C