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Question
- circle all answers that make the inequality true: (x^{2}+3x + 5<9) a. (x = - 1) b. (x = 0) c. (x = 1) d. (x = 2)
Step1: Rearrange the inequality
Subtract 9 from both sides: $x^{2}+3x + 5-9<0$, which simplifies to $x^{2}+3x - 4<0$.
Step2: Factor the quadratic expression
Factor $x^{2}+3x - 4$ as $(x + 4)(x - 1)<0$.
Step3: Find the roots of the corresponding quadratic equation
Set $(x + 4)(x - 1)=0$. The roots are $x=-4$ and $x = 1$. The solution of the inequality $(x + 4)(x - 1)<0$ is $-4Step4: Check each option
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A. $x=-1$, B. $x = 0$