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in circle p, mqo = 131°. solve for x if m∠qpo = (6x + 26)°. if necessar…

Question

in circle p, mqo = 131°. solve for x if m∠qpo = (6x + 26)°. if necessary, round your answer to the nearest tenth.

Explanation:

Step1: Relate arc and central angle

$m\angle QPO = m\overset{\frown}{QO}$

Step2: Set up equation

$6x + 26 = 131$

Step3: Isolate variable term

$6x = 131 - 26$
$6x = 105$

Step4: Solve for x

$x = \frac{105}{6} = 17.5$

Answer:

$x = 17.5$