Question

the circuit shown below has a resistor (a = 28ω) in parallel with a 30ω and a 10ω resistor. part a what is the total current that flows through the circuit? i_t = amperes provide feedback submit request answer

Explanation:

Step1: Calculate parallel - resistance of 10Ω, 30Ω and 28Ω

Use the formula for parallel resistors $\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}$, where $R_1 = 10\Omega$, $R_2=30\Omega$ and $R_3 = 28\Omega$.
$\frac{1}{R_{eq}}=\frac{1}{10}+\frac{1}{30}+\frac{1}{28}=\frac{42 + 14+15}{420}=\frac{71}{420}$
$R_{eq}=\frac{420}{71}\Omega\approx5.915\Omega$

Step2: Calculate total current using Ohm's law

Ohm's law is $I=\frac{V}{R}$, where $V = 4.25V$ and $R = R_{eq}$.
$I_T=\frac{V}{R_{eq}}=\frac{4.25}{\frac{420}{71}}=4.25\times\frac{71}{420}=\frac{301.75}{420}\approx0.72A$

Answer:

$0.72$ Amperes