Question

is circumscribed about the candy bar. if $overline{ad}=3$ cm, what is the smallest diameter of wrapper that will fit the candy bar? 3 cm 4 cm 5 cm 6 cm

Explanation:

Step1: Identify right - triangle

Assume the candy - bar shape is related to a right - triangle formed by the given segments. Let's consider the right - triangle with hypotenuse related to the wrapper's diameter.

Step2: Apply Pythagorean theorem

If we assume the right - triangle has sides \(a\), \(b\), and hypotenuse \(c\) where \(c^{2}=a^{2}+b^{2}\). If we assume the two legs of the right - triangle are \(3\) cm and \(4\) cm (a common right - triangle combination \(3 - 4-5\) right - triangle).
\[c=\sqrt{3^{2}+4^{2}}=\sqrt{9 + 16}=\sqrt{25}=5\]

Answer:

C. 5 cm