Question

click and drag on elements in order. some unsupervised children are having a race with shopping carts. arrange the carts in order of their acceleration, with the fastest at the top. instructions. pushing child exerts a force of 100 n; passenger plus cart is 50 kg. pushing child exerts a force of 90 n; passenger plus cart is 60 kg. pushing child exerts a force of 120 n; passenger plus cart is 40 kg. need help? review these concept resources. read about the concept

Explanation:

Step1: Calculate acceleration for first case

Use Newton's second - law $a = \frac{F}{m}$. For $F = 100\ N$ and $m = 50\ kg$, $a_1=\frac{100}{50}=2\ m/s^{2}$.

Step2: Calculate acceleration for second case

For $F = 90\ N$ and $m = 60\ kg$, $a_2=\frac{90}{60}=1.5\ m/s^{2}$.

Step3: Calculate acceleration for third case

For $F = 120\ N$ and $m = 40\ kg$, $a_3=\frac{120}{40}=3\ m/s^{2}$.

Step4: Compare accelerations

Since $a_3 > a_1 > a_2$.

Answer:

1. Pushing child exerts a force of 120 N; passenger plus cart is 40 kg
2. Pushing child exerts a force of 100 N; passenger plus cart is 50 kg
3. Pushing child exerts a force of 90 N; passenger plus cart is 60 kg