Question

coach belichick is missing tom brady and is pacing on the sideline. he starts in the middle of the field and walks 25 meters towards the patriots end zone then back 30 meters towards the jets end zone. this takes him 15 seconds to do. (please us g = 10 m/s/s for these problems and round to the nearest 100th) what magnitude of the coaches displacement during this time? what is the coaches speed during this time? note: on the real exam you will have to show all work including units and may be asked to create a graph or free body diagram

Explanation:

Step1: Calculate displacement

Displacement is the net change in position. Let the direction towards the Patriot's end - zone be positive. The coach walks 25 meters in the positive direction and then 30 meters in the negative direction. So, the displacement $d$ is $d = 25-30=- 5$ meters. The magnitude of the displacement is $|d| = 5$ meters.

Step2: Calculate speed

Speed is the total distance traveled divided by the time taken. The total distance $D$ traveled is the sum of the distances of each part of the motion. $D=25 + 30=55$ meters. The time taken $t = 15$ seconds. The speed $v$ is given by the formula $v=\frac{D}{t}$. So, $v=\frac{55}{15}\approx3.67$ m/s.

Answer:

Magnitude of displacement: 5 meters
Speed: 3.67 m/s