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∠p and ∠r are complementary and ∠p and ∠q are complementary. complete t…

Question

∠p and ∠r are complementary and ∠p and ∠q are complementary. complete the proof that ∠q ≅ ∠r.
statement | reason

  1. ∠p and ∠r are complementary | given
  2. ∠p and ∠q are complementary | given
  3. ( mangle p + mangle r = 90^circ ) | definition of complementary angles
  4. ( mangle p + mangle q = 90^circ ) | definition of complementary angles
  5. ( mangle p + mangle r = mangle p + mangle q ) | transitive property of equality
  6. ( mangle q = mangle r ) | properties of addition, subtraction, multiplication, and division
  7. ( angle q cong angle r ) | definition of congruence

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Explanation:

Step1: Analyze Statement 4 and 5

Statement 4: \( m\angle P + m\angle Q = 90^\circ \) (from \( \angle P \) and \( \angle Q \) complementary, definition of complementary angles).
Statement 5: \( m\angle P + m\angle R = m\angle P + m\angle Q \)
We know \( m\angle P + m\angle R = 90^\circ \) (from \( \angle P \) and \( \angle R \) complementary, definition of complementary angles, Statement 3). So substituting \( m\angle P + m\angle R = 90^\circ \) into Statement 5, we get \( 90^\circ = m\angle P + m\angle Q \), which matches Statement 4. This uses the Substitution Property of Equality (or from the given reasons, "Properties of addition, subtraction, multiplication, and division" or more precisely, since we have two equal expressions (\( m\angle P + m\angle R = 90^\circ \) and \( m\angle P + m\angle Q = 90^\circ \)) and we set them equal, it's also related to transitive, but the reason for Statement 5 is "Transitive Property of Equality"? Wait, no—wait, Statement 5 is \( m\angle P + m\angle R = m\angle P + m\angle Q \). Let's re-express:

From Statement 3: \( m\angle P + m\angle R = 90^\circ \)
From Statement 4: \( m\angle P + m\angle Q = 90^\circ \)
So by Transitive Property of Equality (if \( a = c \) and \( b = c \), then \( a = b \)), we have \( m\angle P + m\angle R = m\angle P + m\angle Q \). Wait, but the reason for Statement 5 is given as "Transitive Property of Equality"? Wait, no—the user's table has Statement 5 with reason "Transitive Property of Equality"? Wait, the user's table:

Statement 5: \( m\angle P + m\angle R = m\angle P + m\angle Q \)
Reason: Transitive Property of Equality (option given). Wait, no—actually, the correct reason for Statement 5 is using the fact that both \( m\angle P + m\angle R \) and \( m\angle P + m\angle Q \) equal \( 90^\circ \) (from Statements 3 and 4), so by Transitive Property (if \( A = C \) and \( B = C \), then \( A = B \)), we get \( m\angle P + m\angle R = m\angle P + m\angle Q \).

But the question here is likely to fill the reason for Statement 4? Wait, no—looking at the table, Statement 4 is \( m\angle P + m\angle Q = 90^\circ \), Reason: Definition of complementary angles (since \( \angle P \) and \( \angle Q \) are complementary, their measures sum to \( 90^\circ \)).

Wait, the user's table:

  1. \( \angle P \) and \( \angle R \) are complementary: Reason Given
  2. \( \angle P \) and \( \angle Q \) are complementary: Reason Given
  3. \( m\angle P + m\angle R = 90^\circ \): Reason Definition of complementary angles
  4. \( m\angle P + m\angle Q = 90^\circ \): Reason? (The box is for Statement 4? Wait, the image shows Statement 4 with a box for the reason. Wait, Statement 3: \( m\angle P + m\angle R = 90^\circ \), Reason: Definition of complementary angles (correct, since complementary angles sum to \( 90^\circ \)).

Statement 4: \( m\angle P + m\angle Q = 90^\circ \): Reason should be "Definition of complementary angles" (since \( \angle P \) and \( \angle Q \) are complementary, so their measures sum to \( 90^\circ \)), same as Statement 3.

Then Statement 5: \( m\angle P + m\angle R = m\angle P + m\angle Q \): Reason is "Transitive Property of Equality" (since both equal \( 90^\circ \), so they equal each other).

Statement 6: \( m\angle Q = m\angle R \): Reason is "Properties of addition, subtraction, multiplication, and division" (subtract \( m\angle P \) from both sides: \( m\angle P + m\angle R - m\angle P = m\angle P + m\angle Q - m\angle P \implies m\angle R = m\angle Q \), which is subtraction property of equality).

Statement 7: \( \angle Q \cong \angle R \): Reason "De…

Answer:

For Statement 4, the reason is "Definition of complementary angles".