Question

complete the equations.
192 = 1 hundred + 9 tens + 2 ones
192 = 0 hundreds + \square tens + 2 ones
192 = 0 hundreds + 0 tens + \square ones

Explanation:

Step1: Analyze the second equation

We know that \(192 = 0\times100 + \square\times10+ 2\times1\). First, calculate \(0\times100 = 0\) and \(2\times1 = 2\). Then, we can rewrite the equation as \(192=0 + 10\times\square+ 2\). Subtract 2 from both sides: \(192 - 2=10\times\square\), so \(190 = 10\times\square\). To find \(\square\), we divide both sides by 10: \(\square=\frac{190}{10}=19\).

Step2: Analyze the third equation

We know that \(192 = 0\times100+0\times10+\square\times1\). Simplify the left - hand side: \(0\times100 = 0\) and \(0\times10 = 0\). So the equation becomes \(192=0 + 0+\square\times1\), which means \(\square = 192\).

Answer:

For the second equation, the number of tens is \(19\); for the third equation, the number of ones is \(192\).

So the completed equations are:
\(192 = 0\) hundreds \(+\boldsymbol{19}\) tens \(+ 2\) ones
\(192 = 0\) hundreds \(+ 0\) tens \(+\boldsymbol{192}\) ones