Question

complete the equations.

489 = 4 hundreds + 8 tens + 9 ones

489 = 0 hundreds + \square tens + 9 ones

489 = 0 hundreds + 0 tens + \square ones

Explanation:

Step1: Analyze the second equation

We know that \(489 = 0\times100 + \square\times10 + 9\times1\). First, calculate \(0\times100 = 0\) and \(9\times1 = 9\). Then, we can rewrite the equation as \(489=0 + 10\square+ 9\). Subtract 9 from both sides: \(489 - 9=10\square\), so \(480 = 10\square\). Divide both sides by 10: \(\square=\frac{480}{10}=48\).

Step2: Analyze the third equation

We know that \(489 = 0\times100 + 0\times10+\square\times1\). Calculate \(0\times100 = 0\) and \(0\times10 = 0\). Then the equation becomes \(489 = 0 + 0+\square\), so \(\square = 489\).

Answer:

For the second equation, the number of tens is \(48\). For the third equation, the number of ones is \(489\). So the filled equations are:
\(489 = 0\) hundreds \(+\boldsymbol{48}\) tens \(+ 9\) ones
\(489 = 0\) hundreds \(+ 0\) tens \(+\boldsymbol{489}\) ones