Question

complete the following statement. use the integers that are closest to the number in the middle. $square < sqrt{41} < square$
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Explanation:

Step1: Find nearest lower square

$6^2 = 36$

Step2: Find nearest upper square

$7^2 = 49$

Step3: Compare to $\sqrt{41}$

Since $36 < 41 < 49$, take square roots: $\sqrt{36} < \sqrt{41} < \sqrt{49}$

Answer:

$6 < \sqrt{41} < 7$