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Question
complete the following statement. use the integers that are closest to the number in middle.
$\square < -\sqrt{34} < \square$
Step1: Find perfect squares around 34
We know that $5^2 = 25$ and $6^2 = 36$. Since $25<34<36$, we have $\sqrt{25}<\sqrt{34}<\sqrt{36}$, which simplifies to $5 < \sqrt{34} < 6$.
Step2: Apply the negative sign
When we multiply all parts of the inequality by $- 1$, the direction of the inequality signs changes. So we get $-6<-\sqrt{34}<-5$.
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$-6 < -\sqrt{34} < -5$ (So the first box is -6 and the second box is -5)