Question

compute the value of the discriminant and give the number of real solutions of the quadratic equation.
$-2x^{2}-2x - 9 = 0$

discriminant:
number of real solutions:

Explanation:

Step1: Identify quadratic coefficients

For $-2x^2 -2x -9=0$, $a=-2$, $b=-2$, $c=-9$

Step2: Apply discriminant formula

Discriminant $D = b^2 - 4ac$
$D = (-2)^2 - 4(-2)(-9)$

Step3: Calculate discriminant value

$D = 4 - 72 = -68$

Step4: Determine real solutions

If $D<0$, no real solutions exist.

Answer:

Discriminant: $-68$
Number of real solutions: $0$