Question

consecutive integer problems - linear (level 1)
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question
hannah is the oldest of four siblings whose ages are consecutive integers. if the sum of their ages is 86, find hannahs age.
answer attempt 1 out of 3
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Explanation:

Step1: Define variables for ages

Let the ages of the four siblings be \( x - 3 \), \( x - 2 \), \( x - 1 \), and \( x \) (where \( x \) is Hannah's age, the oldest). The sum of their ages is 86.

Step2: Set up the equation

The sum of the ages is \((x - 3)+(x - 2)+(x - 1)+x = 86\).
Simplify the left - hand side: \(x-3+x - 2+x - 1+x=4x-(3 + 2+1)=4x - 6\).
So the equation is \(4x-6 = 86\).

Step3: Solve for x

Add 6 to both sides of the equation: \(4x-6 + 6=86 + 6\), which gives \(4x=92\).
Divide both sides by 4: \(x=\frac{92}{4}=23\).

Answer:

23