Question

consider the following function.
h(x)=\frac{10}{7}x^{5}
step 2 of 2: find two points on the graph of this function, other than the origin, that fit within the given (-10,10) by (-10,10) grid. express each coordinate as an integer or simplified fraction, or round to four decimal places as necessary.

Explanation:

Step1: Choose an \(x\) - value

Let \(x = 1\).

Step2: Calculate the corresponding \(y\) - value

Substitute \(x = 1\) into \(h(x)=\frac{10}{7}x^{5}\). Then \(h(1)=\frac{10}{7}(1)^{5}=\frac{10}{7}\approx1.4286\). So one point is \((1,\frac{10}{7})\).

Step3: Choose another \(x\) - value

Let \(x=- 1\).

Step4: Calculate the corresponding \(y\) - value

Substitute \(x = - 1\) into \(h(x)=\frac{10}{7}x^{5}\). Then \(h(-1)=\frac{10}{7}(-1)^{5}=-\frac{10}{7}\approx - 1.4286\). So another point is \((-1,-\frac{10}{7})\).

Answer:

\((1,\frac{10}{7}),(-1,-\frac{10}{7})\)