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consider △lmn. m∠l + m∠m = < sin(l) = < sin(m) = <

Question

consider △lmn. m∠l + m∠m =
<
sin(l) =
<
sin(m) =
<

Explanation:

Step1: Recall angle - sum property

In a right - triangle $\triangle LMN$ with $\angle N = 90^{\circ}$, $\angle L=42^{\circ}$ and $\angle M = 48^{\circ}$.

Step2: Find sine values

$\sin(M)=\sin(48^{\circ})\approx0.7431$, $\sin(L)=\sin(42^{\circ})\approx0.6691$.

Step3: Calculate angle sum

$m\angle L + m\angle M=42^{\circ}+48^{\circ}=90^{\circ}$

Answer:

$\sin(M)\approx0.7431$, $\sin(L)\approx0.6691$, $m\angle L + m\angle M = 90^{\circ}$