Question

y = 4 - \frac{1}{3}x\
\

x	y	\
		\
		\
		\
		\
		\

\
(coordinate grid with x and y axes)

Explanation:

Step1: Pick x-values, solve for y

Choose \(x = -3, 0, 3, 6, 9\) (multiples of 3 to simplify calculation):

• For \(x=-3\): \(y = 4 - \frac{1}{3}(-3) = 4 + 1 = 5\)
• For \(x=0\): \(y = 4 - \frac{1}{3}(0) = 4\)
• For \(x=3\): \(y = 4 - \frac{1}{3}(3) = 4 - 1 = 3\)
• For \(x=6\): \(y = 4 - \frac{1}{3}(6) = 4 - 2 = 2\)
• For \(x=9\): \(y = 4 - \frac{1}{3}(9) = 4 - 3 = 1\)

Step2: Tabulate the (x,y) pairs

Organize calculated values into the table:

\(x\)	\(y\)
\(0\)	\(4\)
\(3\)	\(3\)
\(6\)	\(2\)
\(9\)	\(1\)

Step3: Plot points, draw the line

Plot the points \((-3,5)\), \((0,4)\), \((3,3)\), \((6,2)\), \((9,1)\) on the coordinate grid, then draw a straight line through them (this line represents \(y=4-\frac{1}{3}x\)).

Answer:

Completed Table:

\(x\)	\(y\)
\(0\)	\(4\)
\(3\)	\(3\)
\(6\)	\(2\)
\(9\)	\(1\)

Graph Description:

A straight line passing through the points \((-3,5)\), \((0,4)\), \((3,3)\), \((6,2)\), \((9,1)\) with a slope of \(-\frac{1}{3}\) and y-intercept at \((0,4)\).