Question

the coordinates of the vertices of a triangle are n (-5,2), p (-5,-5), and q (1,-6). triangle npq is reflected across the x - axis to create triangle npq. what are the coordinates of the vertices of triangle npq? n = p =

Explanation:

Step1: Recall reflection rule

When reflecting a point $(x,y)$ across the x - axis, the rule is $(x,y)\to(x, - y)$.

Step2: Find coordinates of $N'$

For point $N(-5,2)$, applying the rule: $x=-5,y = 2$, so $N'=(-5,-2)$.

Step3: Find coordinates of $P'$

For point $P(-5,-5)$, applying the rule: $x=-5,y=-5$, so $P'=(-5,5)$.

Step4: Find coordinates of $Q'$

For point $Q(1,-6)$, applying the rule: $x = 1,y=-6$, so $Q'=(1,6)$.

Answer:

$N'=(-5,-2)$
$P'=(-5,5)$
$Q'=(1,6)$