Question

1. a 6×6 cube made of individual blocks is positioned so that exactly three faces of the cube are visible at one time, as shown in the image. how many individual blocks can be seen from this position?

Explanation:

Step1: Calculate blocks on first face

The first visible face has $6\times6 = 36$ blocks.

Step2: Calculate blocks on second face

The second visible face (not double - counting common edge) has $6\times(6 - 1)=30$ blocks.

Step3: Calculate blocks on third face

The third visible face (not double - counting common edges) has $(6 - 1)\times(6 - 1)=25$ blocks.

Step4: Sum up the blocks

Sum of blocks is $36+30 + 25=91$.

Answer:

91