Question

6 v= ______ cubic meters 9 v= ______ cubic feet

Explanation:

Step1: Consider the large cuboid

The dimensions of the large cuboid that would enclose the given shape are length $l = 10$ m, width $w=6$ m and height $h = 6$ m. Its volume $V_{total}=l\times w\times h=10\times6\times6 = 360$ m³.

Step2: Consider the small - removed cuboid

The small cuboid that is removed has length $l = 10$ m, width $w = 3$ m and height $h=3$ m. Its volume $V_{removed}=l\times w\times h=10\times3\times3=90$ m³.

Step3: Calculate the volume of the given shape

The volume of the given shape $V = V_{total}-V_{removed}$. So $V=360 - 90=270$ m³.

Answer:

270