Question

a culture of $1.75\times10^{18}$ bacteria is in petri - dish a. a culture of $6.25\times10^{15}$ bacteria is in petri - dish b. how many times greater is the number of bacteria in petri dish a than petri dish b? enter your answer, in standard notation, in the box.

Explanation:

Step1: Set up the division

To find out how many times greater the number of bacteria in petri - dish A is than in petri - dish B, we divide the number of bacteria in dish A by the number of bacteria in dish B. So we have the expression $\frac{1.75\times10^{18}}{6.25\times10^{15}}$.

Step2: Separate the coefficients and exponents

Using the rule $\frac{a\times10^{m}}{b\times10^{n}}=\frac{a}{b}\times10^{m - n}$, we get $\frac{1.75}{6.25}\times10^{18 - 15}$.

Step3: Calculate the coefficient and exponent

First, calculate $\frac{1.75}{6.25}=0.28$. Then, $18−15 = 3$, so we have $0.28\times10^{3}$.

Step4: Convert to standard notation

Since $0.28\times10^{3}$, we move the decimal point 3 places to the right. $0.28\times10^{3}=280$.

Answer:

280