Question

current attempt in progress
how many joules of heat are required to heat 180 g of aluminum from 16.0 °c to 50.5 °c?
table 4.3 | specific heat of selected substances

substance	specific heat (j/g°c)	specific heat (cal/g°c)
ethyl alcohol	2.138	0.511
ice	2.059	0.492
aluminum	0.900	0.215
iron	0.473	0.113
copper	0.385	0.0921
gold	0.131	0.0312
lead	0.128	0.0305

etextbook and media
save for later
attempts: 0

Explanation:

Step1: Identify the formula

The formula for heat $Q$ is $Q = mc\Delta T$, where $m$ is the mass, $c$ is the specific - heat capacity, and $\Delta T$ is the change in temperature.

Step2: Determine the values

$m = 180\ g$, $c = 0.900\ J/g^{\circ}C$ (specific heat of aluminum from the table), $\Delta T=T_2 - T_1=50.5^{\circ}C - 16.0^{\circ}C = 34.5^{\circ}C$.

Step3: Calculate the heat

$Q=mc\Delta T=180\ g\times0.900\ J/g^{\circ}C\times34.5^{\circ}C$.
$Q = 180\times0.900\times34.5\ J$.
$Q = 5589\ J$.

Answer:

$5589$