Question

the data in the table represents pulses of males measured at a blood drive.
pulse
56 60 68 76
56 60 68 84
56 60 68 84
56 64 72 84
56 64 72 84
56 64 72 88
60 64 72 88
60 64 72 88
60 64 72 88
60 64 76 102
find the iqr. iqr=
find the lower fence for outliers. lf=
find the upper fence for outliers. uf=
this data set has one outlier. what is the outlier?

Explanation:

Step1: Arrange data in ascending order

56, 56, 56, 56, 56, 56, 60, 60, 60, 60, 60, 60, 64, 64, 64, 64, 64, 64, 68, 68, 68, 72, 72, 72, 72, 76, 76, 84, 84, 84, 84, 88, 88, 88, 88, 102

Step2: Find the median (Q2)

There are 35 data - points. The median is the 18th value. So, Q2 = 64.

Step3: Find Q1

The lower half of the data has 17 values. The median of the lower half (Q1) is the 9th value. So, Q1 = 60.

Step4: Find Q3

The upper half of the data has 17 values. The median of the upper half (Q3) is the 27th value. So, Q3 = 84.

Step5: Calculate the IQR

IQR = Q3 - Q1 = 84 - 60 = 24.

Step6: Calculate the lower fence for outliers

LF=Q1 - 1.5×IQR = 60 - 1.5×24 = 60 - 36 = 24.

Step7: Calculate the upper fence for outliers

UF=Q3 + 1.5×IQR = 84+1.5×24 = 84 + 36 = 120.

Step8: Identify the outlier

Since all values except 102 are within the range of 24 to 120, the outlier is 102.

Answer:

IQR = 24
LF = 24
UF = 120
Outlier = 102