Question

describe and correct the error a student made in finding the midpoint of cd with c(-4,5) and d(-1,-4). (\frac{-4 - (-1)}{2},\frac{5-(-4)}{2}) (\frac{3}{2},\frac{9}{2}) x c. the student did not divide the numerator and denominator by 2 when calculating the midpoint. d. the student did not add the x - and y - coordinates when calculating the midpoint. the correct answer is _. (type an ordered pair, using integers or fractions.) video textbook get more help

Explanation:

Step1: Recall mid - point formula

The mid - point formula for two points $(x_1,y_1)$ and $(x_2,y_2)$ is $(\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$. Here $x_1=-4,y_1 = 5,x_2=-1,y_2=-4$.

Step2: Calculate x - coordinate of mid - point

$x=\frac{-4+( - 1)}{2}=\frac{-4 - 1}{2}=-\frac{5}{2}$

Step3: Calculate y - coordinate of mid - point

$y=\frac{5+( - 4)}{2}=\frac{5 - 4}{2}=\frac{1}{2}$

Answer:

$(-\frac{5}{2},\frac{1}{2})$