QUESTION IMAGE
Question
describe a series of transformations that maps figure 1 to figure 2 to figure 3. be specific.
4.
5.
describe the transformation or sequence of transformations that map each of the preimages to the images listed below.
- abcd → ghcd
- mnop → abcd
- rqop → lmjk
- gfed → rqop
Problem 4:
Step1: Map Figure 1 to Figure 2
To map Figure 1 to Figure 2, we perform a translation (vertical shift) upwards. Let's assume each grid square has a side length of 1 unit. By observing the vertical distance between Figure 1 and Figure 2, we can see that Figure 1 is shifted up by 3 units to get Figure 2. Mathematically, if we consider the coordinates of the vertices of Figure 1, adding 3 to the y - coordinate of each vertex will map it to Figure 2.
Step2: Map Figure 2 to Figure 3
To map Figure 2 to Figure 3, we perform a translation (horizontal and vertical shift). First, we shift Figure 2 horizontally to the right and vertically upwards. By observing the grid, Figure 2 is shifted right by 5 units and up by 3 units to get Figure 3. So, we add 5 to the x - coordinate and 3 to the y - coordinate of each vertex of Figure 2.
Step1: Map Figure 1 to Figure 4
To map Figure 1 to Figure 4, we perform a reflection over the y - axis. A reflection over the y - axis changes the sign of the x - coordinate of each vertex. If a vertex of Figure 1 has coordinates \((x,y)\), after reflection over the y - axis, it will have coordinates \((-x,y)\).
Step2: Map Figure 4 to Figure 2
To map Figure 4 to Figure 2, we perform a translation (vertical shift) downwards. By observing the grid, Figure 4 is shifted down by 6 units to get Figure 2. So, we subtract 6 from the y - coordinate of each vertex of Figure 4.
Looking at the figures, \(ABCD\) and \(GHCD\) share the side \(CD\). To map \(ABCD\) to \(GHCD\), we can perform a reflection over the vertical line passing through \(CD\) (or a horizontal reflection depending on the orientation). Alternatively, we can see that it is a reflection (or a translation and reflection combination, but more likely a reflection) such that the part of \(ABCD\) with vertices \(A\) and \(B\) is mapped to \(G\) and \(H\) while \(C\) and \(D\) remain fixed (since \(CD\) is common). A reflection over the line perpendicular to \(AB\) and \(GH\) (which is the vertical line through \(CD\)) will map \(A\) to \(G\) and \(B\) to \(H\) while keeping \(C\) and \(D\) in place.
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To map Figure 1 to Figure 2: Translate Figure 1 3 units up. To map Figure 2 to Figure 3: Translate Figure 2 5 units right and 3 units up.