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Question
determine the ( x )-intercepts of the following equation. ((-5x - 25)(4x + 16) = y) answer ( (-5,0) ) and ( (4,0) ) ( (-5,0) ) and ( (-4,0) ) ( (-400,0) ) ( (0,400) ) ( (0,-5) ) and ( (0,-4) ) ( (0,-400) )
Step1: Recall x-intercept definition
x-intercepts occur where \( y = 0 \). So set \( y = 0 \) in the equation \( (-5x - 25)(4x + 16)=y \), getting \( (-5x - 25)(4x + 16)=0 \).
Step2: Solve each factor
For a product to be zero, at least one factor is zero.
- Solve \( -5x - 25 = 0 \):
Add 25 to both sides: \( -5x = 25 \), divide by -5: \( x = -5 \).
- Solve \( 4x + 16 = 0 \):
Subtract 16: \( 4x = -16 \), divide by 4: \( x = -4 \).
So the x-intercepts are when \( x = -5 \) (y=0) and \( x = -4 \) (y=0), i.e., \( (-5, 0) \) and \( (-4, 0) \).
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\( (-5,0) \) and \( (-4,0) \)