Question

in the diagram below, what will the acceleration of the box be? 70 n 245 n 350 n 25 kg 245 n a 11.2 m/s² b 14 m/s² c 9.8 m/s² d 16.8 m/s²

Explanation:

Step1: Calculate net - force in x - direction

The forces in the y - direction (245 N up and 245 N down) cancel each other out. The net - force in the x - direction $F_{net,x}=350 - 70=280$ N.

Step2: Use Newton's second law

Newton's second law is $F = ma$, where $F$ is the net - force, $m$ is the mass, and $a$ is the acceleration. We know $F_{net,x}=280$ N and $m = 25$ kg. Rearranging for $a$, we get $a=\frac{F_{net,x}}{m}$.

Step3: Calculate the acceleration

$a=\frac{280}{25}=11.2$ m/s².

Answer:

A. 11.2 m/s²