Question

differentiate.
y = 2\sqrt{x}
\frac{d}{dx}(2\sqrt{x}) = square

Explanation:

Step1: Rewrite the function

$y = 2x^{\frac{1}{2}}$

Step2: Apply power - rule

$\frac{d}{dx}(ax^n)=anx^{n - 1}$, so $\frac{d}{dx}(2x^{\frac{1}{2}})=2\times\frac{1}{2}x^{\frac{1}{2}-1}$

Step3: Simplify the result

$x^{-\frac{1}{2}}=\frac{1}{\sqrt{x}}$

Answer:

$\frac{1}{\sqrt{x}}$