Question

directions: solve for x in each equation below. your first step should be to combine any like terms. then use inverse operations to get the variable all by itself on one side of the equation. make sure to show your work
examples: 3x + 12 + x = 48 (add 3x + x)
4x + 12 = 48 (subtract 12 from both sides)
4x = 36 (divide both sides by 4)
x = 9
3x + 12 + 2 = 25 (add 12 + 2)
3x + 14 = 25 (subtract 14 from both sides)
3x = 12 (divide both sides by 3)
x = 4

1. 3x + 10 + 2x = 50
2. 6x + 10 + 2x = 42
3. 2x + 20 + 2x = 60
4. x + 12 + x = 18

x =
x =
x =
x =

1. 7x + 10 + 3x = 120
2. x + 20 + 2x = 56
3. 2x + 16 + 2x = 28
4. 3x + 12 + 9x = 72

x =
x =
x =
x =

1. 3 + 6x + 2 = 29
2. 7 + 7x + 2 = 72
3. 2x + 20 + 2 = 60
4. x + 4x + 1 = 26

x =
x =
x =
x =

Explanation:

Problem 1: \( 3x + 10 + 2x = 50 \)

Step1: Combine like terms (\(3x + 2x\))

\( 5x + 10 = 50 \)

Step2: Subtract 10 from both sides

\( 5x = 50 - 10 \)
\( 5x = 40 \)

Step3: Divide both sides by 5

\( x = \frac{40}{5} \)
\( x = 8 \)

Step1: Combine like terms (\(6x + 2x\))

\( 8x + 10 = 42 \)

Step2: Subtract 10 from both sides

\( 8x = 42 - 10 \)
\( 8x = 32 \)

Step3: Divide both sides by 8

\( x = \frac{32}{8} \)
\( x = 4 \)

Step1: Combine like terms (\(2x + 2x\))

\( 4x + 20 = 60 \)

Step2: Subtract 20 from both sides

\( 4x = 60 - 20 \)
\( 4x = 40 \)

Step3: Divide both sides by 4

\( x = \frac{40}{4} \)
\( x = 10 \)

Answer:

\( x = 8 \)

Problem 2: \( 6x + 10 + 2x = 42 \)