QUESTION IMAGE
Question
dividing 2 digits
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33 is between 32 and 40, so 33 \div 8 is between 4 and 5. the ones digit is 4.
since 33 - 32 = 1 and 1 is less than 8, the remainder 1 is recorded like this:
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\text{r}1
divide.
1.
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2.
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3.
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4.
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Step1: Solve 1a: 26 ÷ 5
Find largest multiple of 5 ≤26: $5×5=25$. Subtract: $26-25=1$.
Step2: Solve 1b: 58 ÷ 7
Find largest multiple of 7 ≤58: $7×8=56$. Subtract: $58-56=2$.
Step3: Solve 1c: 31 ÷ 4
Find largest multiple of 4 ≤31: $4×7=28$. Subtract: $31-28=3$.
Step4: Solve 1d: 82 ÷ 9
Find largest multiple of 9 ≤82: $9×9=81$. Subtract: $82-81=1$.
Step5: Solve 1e: 35 ÷ 6
Find largest multiple of 6 ≤35: $6×5=30$. Subtract: $35-30=5$.
Step6: Solve 2a: 66 ÷ 8
Find largest multiple of 8 ≤66: $8×8=64$. Subtract: $66-64=2$.
Step7: Solve 2b: 17 ÷ 3
Find largest multiple of 3 ≤17: $3×5=15$. Subtract: $17-15=2$.
Step8: Solve 2c: 13 ÷ 2
Find largest multiple of 2 ≤13: $2×6=12$. Subtract: $13-12=1$.
Step9: Solve 2d: 50 ÷ 7
Find largest multiple of 7 ≤50: $7×7=49$. Subtract: $50-49=1$.
Step10: Solve 2e: 40 ÷ 6
Find largest multiple of 6 ≤40: $6×6=36$. Subtract: $40-36=4$.
Step11: Solve 3a: 30 ÷ 9
Find largest multiple of 9 ≤30: $9×3=27$. Subtract: $30-27=3$.
Step12: Solve 3b: 41 ÷ 5
Find largest multiple of 5 ≤41: $5×8=40$. Subtract: $41-40=1$.
Step13: Solve 3c: 10 ÷ 3
Find largest multiple of 3 ≤10: $3×3=9$. Subtract: $10-9=1$.
Step14: Solve 3d: 73 ÷ 8
Find largest multiple of 8 ≤73: $8×9=72$. Subtract: $73-72=1$.
Step15: Solve 3e: 57 ÷ 7
Find largest multiple of 7 ≤57: $7×8=56$. Subtract: $57-56=1$.
Step16: Solve 4a: 20 ÷ 8
Find largest multiple of 8 ≤20: $8×2=16$. Subtract: $20-16=4$.
Step17: Solve 4b: 37 ÷ 6
Find largest multiple of 6 ≤37: $6×6=36$. Subtract: $37-36=1$.
Step18: Solve 4c: 55 ÷ 9
Find largest multiple of 9 ≤55: $9×6=54$. Subtract: $55-54=1$.
Step19: Solve 4d: 29 ÷ 7
Find largest multiple of 7 ≤29: $7×4=28$. Subtract: $29-28=1$.
Step20: Solve 4e: 47 ÷ 5
Find largest multiple of 5 ≤47: $5×9=45$. Subtract: $47-45=2$.
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