Question

draw the image of △abc under the translation (x,y)→(x,y + 3).

Explanation:

Step1: Identify vertex coordinates

Let's assume the coordinates of vertices of $\triangle ABC$ are $A(x_1,y_1)$, $B(x_2,y_2)$, $C(x_3,y_3)$. From the graph, if we assume $A(- 3,-3)$, $B(0,0)$, $C(-6,2)$.

Step2: Apply the translation rule

The translation rule is $(x,y)\to(x,y + 3)$.
For point $A(-3,-3)$: The new - coordinates are $A'(-3,-3 + 3)=A'(-3,0)$.
For point $B(0,0)$: The new - coordinates are $B'(0,0 + 3)=B'(0,3)$.
For point $C(-6,2)$: The new - coordinates are $C'(-6,2 + 3)=C'(-6,5)$.

Step3: Plot the new triangle

Plot the points $A'(-3,0)$, $B'(0,3)$ and $C'(-6,5)$ on the coordinate - plane and connect them to form the image of $\triangle ABC$.

Answer:

Plot points $A'(-3,0)$, $B'(0,3)$ and $C'(-6,5)$ and connect them to get the translated triangle.