Question

draw the image of quadrilateral abcd under a translation by 2 units to the right and 5 units down.

Explanation:

Step1: Identify original coordinates

Original points:
$A(-4, 1)$, $B(3, -1)$, $C(4, 1)$, $D(-5, 3)$

Step2: Apply translation rule

Translation: $(x+2, y-5)$

• $A'$: $(-4+2, 1-5) = (-2, -4)$
• $B'$: $(3+2, -1-5) = (5, -6)$
• $C'$: $(4+2, 1-5) = (6, -4)$
• $D'$: $(-5+2, 3-5) = (-3, -2)$

Step3: Plot and connect points

Plot $A'(-2,-4)$, $B'(5,-6)$, $C'(6,-4)$, $D'(-3,-2)$, then connect them in order.

Answer:

The coordinates of the translated quadrilateral $A'B'C'D'$ are:
$A'(-2, -4)$, $B'(5, -6)$, $C'(6, -4)$, $D'(-3, -2)$
(When drawn on the grid, connect these four points to form the translated quadrilateral.)