QUESTION IMAGE
Question
*each one is only used once
column a
- _h 100 mg × ______ = 0.1 g
- _c 20 cm × ______ = 0.2 m
- _d 50 l × ______ = 0.050 kl
- _g 22 g ______ = 2,200 cg
- _f 825 cm ______ = 0.00825 km
- _e 2,350 kg ______ = 2,350,000 g
- _a 19 ml ______ = 1.9 cl
- __ 52 km ____ = 52,000 m
- _i 36 m ______ = 3,600 cm
- 18 cm ______ = 180 mm
- _b 6 g ______ = 6,000 mg
- _l 4,259 ml ______ = 4.259 l
column b
a. \\(\frac{1\text{l}}{1000\text{ml}}\\)
b. \\(\frac{1000\text{mg}}{1\text{g}}\\)
c. \\(\frac{1\text{m}}{100\text{cm}}\\)
d. \\(\frac{1\text{kl}}{1000\text{l}}\\)
e. \\(\frac{1000\text{g}}{1\text{kg}}\\)
f. \\(\frac{1\text{m}}{100\text{cm}} \times \frac{1000\text{mm}}{1\text{m}}\\)
g. \\(\frac{100\text{cg}}{1\text{g}}\\)
h. \\(\frac{1\text{g}}{1000\text{mg}}\\)
i. \\(\frac{100\text{cm}}{1\text{m}}\\)
j. \\(\frac{1\text{m}}{100\text{cm}} \times \frac{1\text{km}}{1000\text{m}}\\)
k. \\(\frac{1000\text{m}}{1\text{km}}\\)
l. (conversion factor for 4,259 ml to 4.259 l, corresponding to option l.)
To solve this problem, we need to match each conversion in Column A with the appropriate conversion factor from Column B. Let's analyze each item:
Item 8: \( 52 \, \text{km} \times \_\_\_\_\_\_ = 52,000 \, \text{m} \)
We know that \( 1 \, \text{km} = 1000 \, \text{m} \), so the conversion factor is \( \frac{1000 \, \text{m}}{1 \, \text{km}} \) (or \( \frac{1000 \, \text{m}}{1 \, \text{km}} \) can be written as \( \frac{1000 \, \text{m}}{1 \, \text{km}} \), but looking at Column B, the option \( k \) is \( \frac{1000 \, \text{m}}{1 \, \text{km}} \). Let's verify:
\( 52 \, \text{km} \times \frac{1000 \, \text{m}}{1 \, \text{km}} = 52 \times 1000 \, \text{m} = 52,000 \, \text{m} \), which matches.
Item 10: \( 18 \, \text{cm} \times \_\_\_\_\_\_ = 180 \, \text{mm} \)
We know that \( 1 \, \text{cm} = 10 \, \text{mm} \), but let's check Column B. Wait, maybe I made a mistake. Wait, \( 1 \, \text{cm} = 10 \, \text{mm} \), so \( 18 \, \text{cm} \times 10 \, \text{mm/cm} = 180 \, \text{mm} \). But looking at Column B, option \( j \)? No, wait, option \( j \) is \( \frac{1 \, \text{m}}{100 \, \text{cm}} \times \frac{1 \, \text{km}}{1000 \, \text{m}} \), no. Wait, maybe \( 1 \, \text{cm} = 10 \, \text{mm} \), so the conversion factor is \( \frac{10 \, \text{mm}}{1 \, \text{cm}} \), but Column B has option \( j \)? Wait, no, let's re - check. Wait, \( 1 \, \text{cm}=10 \, \text{mm} \), so \( 18 \, \text{cm} \times \frac{10 \, \text{mm}}{1 \, \text{cm}} = 180 \, \text{mm} \). But in Column B, is there an option? Wait, maybe I misread. Wait, the options:
- \( k \): \( \frac{1000 \, \text{m}}{1 \, \text{km}} \) (for item 8)
- For item 10, let's see: \( 1 \, \text{cm} = 10 \, \text{mm} \), so the conversion factor is \( \frac{10 \, \text{mm}}{1 \, \text{cm}} \), but in Column B, maybe option \( j \) is not. Wait, maybe I made a mistake. Wait, the original problem:
Wait, the user's problem is to match the columns. Let's list all items:
- \( 100 \, \text{mg} \times \_\_ = 0.1 \, \text{g} \): \( 1 \, \text{g}=1000 \, \text{mg} \), so \( \frac{1 \, \text{g}}{1000 \, \text{mg}} \) (option h)
- \( 20 \, \text{cm} \times \_\_ = 0.2 \, \text{m} \): \( 1 \, \text{m}=100 \, \text{cm} \), so \( \frac{1 \, \text{m}}{100 \, \text{cm}} \) (option c)
- \( 50 \, \text{L} \times \_\_ = 0.050 \, \text{kL} \): \( 1 \, \text{kL}=1000 \, \text{L} \), so \( \frac{1 \, \text{kL}}{1000 \, \text{L}} \) (option d)
- \( 22 \, \text{g} \times \_\_ = 2200 \, \text{cg} \): \( 1 \, \text{g}=100 \, \text{cg} \), so \( \frac{100 \, \text{cg}}{1 \, \text{g}} \) (option g)
- \( 825 \, \text{cm} \times \_\_ = 0.00825 \, \text{km} \): First, \( 1 \, \text{m}=100 \, \text{cm} \) and \( 1 \, \text{km}=1000 \, \text{m} \), so \( \frac{1 \, \text{m}}{100 \, \text{cm}} \times \frac{1 \, \text{km}}{1000 \, \text{m}}=\frac{1 \, \text{km}}{100000 \, \text{cm}} \), but option f is \( \frac{1 \, \text{m}}{100 \, \text{cm}} \times \frac{1 \, \text{km}}{1000 \, \text{m}} \), so \( 825 \, \text{cm} \times \frac{1 \, \text{m}}{100 \, \text{cm}} \times \frac{1 \, \text{km}}{1000 \, \text{m}}=825\times\frac{1}{100}\times\frac{1}{1000}\, \text{km}=0.00825 \, \text{km} \) (option f)
- \( 2350 \, \text{kg} \times \_\_ = 2350000 \, \text{g} \): \( 1 \, \text{kg}=1000 \, \text{g} \), so \( \frac{1000 \, \text{g}}{1 \, \text{kg}} \) (option e)
- \( 19 \, \text{mL} \times \_\_ = 1.9 \, \text{cL} \): \( 1 \, \text{cL}=10 \, \text{mL} \), so \( \frac{1 \, \text{cL}}{10 \, \text{mL}} \), but option a is \( \frac{1 \, \text{L}}{1000 \, \text{mL}} \)? Wait, no, \( 1 \, \text{cL} = 10 \, \text{…
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To solve this problem, we need to match each conversion in Column A with the appropriate conversion factor from Column B. Let's analyze each item:
Item 8: \( 52 \, \text{km} \times \_\_\_\_\_\_ = 52,000 \, \text{m} \)
We know that \( 1 \, \text{km} = 1000 \, \text{m} \), so the conversion factor is \( \frac{1000 \, \text{m}}{1 \, \text{km}} \) (or \( \frac{1000 \, \text{m}}{1 \, \text{km}} \) can be written as \( \frac{1000 \, \text{m}}{1 \, \text{km}} \), but looking at Column B, the option \( k \) is \( \frac{1000 \, \text{m}}{1 \, \text{km}} \). Let's verify:
\( 52 \, \text{km} \times \frac{1000 \, \text{m}}{1 \, \text{km}} = 52 \times 1000 \, \text{m} = 52,000 \, \text{m} \), which matches.
Item 10: \( 18 \, \text{cm} \times \_\_\_\_\_\_ = 180 \, \text{mm} \)
We know that \( 1 \, \text{cm} = 10 \, \text{mm} \), but let's check Column B. Wait, maybe I made a mistake. Wait, \( 1 \, \text{cm} = 10 \, \text{mm} \), so \( 18 \, \text{cm} \times 10 \, \text{mm/cm} = 180 \, \text{mm} \). But looking at Column B, option \( j \)? No, wait, option \( j \) is \( \frac{1 \, \text{m}}{100 \, \text{cm}} \times \frac{1 \, \text{km}}{1000 \, \text{m}} \), no. Wait, maybe \( 1 \, \text{cm} = 10 \, \text{mm} \), so the conversion factor is \( \frac{10 \, \text{mm}}{1 \, \text{cm}} \), but Column B has option \( j \)? Wait, no, let's re - check. Wait, \( 1 \, \text{cm}=10 \, \text{mm} \), so \( 18 \, \text{cm} \times \frac{10 \, \text{mm}}{1 \, \text{cm}} = 180 \, \text{mm} \). But in Column B, is there an option? Wait, maybe I misread. Wait, the options:
- \( k \): \( \frac{1000 \, \text{m}}{1 \, \text{km}} \) (for item 8)
- For item 10, let's see: \( 1 \, \text{cm} = 10 \, \text{mm} \), so the conversion factor is \( \frac{10 \, \text{mm}}{1 \, \text{cm}} \), but in Column B, maybe option \( j \) is not. Wait, maybe I made a mistake. Wait, the original problem:
Wait, the user's problem is to match the columns. Let's list all items:
- \( 100 \, \text{mg} \times \_\_ = 0.1 \, \text{g} \): \( 1 \, \text{g}=1000 \, \text{mg} \), so \( \frac{1 \, \text{g}}{1000 \, \text{mg}} \) (option h)
- \( 20 \, \text{cm} \times \_\_ = 0.2 \, \text{m} \): \( 1 \, \text{m}=100 \, \text{cm} \), so \( \frac{1 \, \text{m}}{100 \, \text{cm}} \) (option c)
- \( 50 \, \text{L} \times \_\_ = 0.050 \, \text{kL} \): \( 1 \, \text{kL}=1000 \, \text{L} \), so \( \frac{1 \, \text{kL}}{1000 \, \text{L}} \) (option d)
- \( 22 \, \text{g} \times \_\_ = 2200 \, \text{cg} \): \( 1 \, \text{g}=100 \, \text{cg} \), so \( \frac{100 \, \text{cg}}{1 \, \text{g}} \) (option g)
- \( 825 \, \text{cm} \times \_\_ = 0.00825 \, \text{km} \): First, \( 1 \, \text{m}=100 \, \text{cm} \) and \( 1 \, \text{km}=1000 \, \text{m} \), so \( \frac{1 \, \text{m}}{100 \, \text{cm}} \times \frac{1 \, \text{km}}{1000 \, \text{m}}=\frac{1 \, \text{km}}{100000 \, \text{cm}} \), but option f is \( \frac{1 \, \text{m}}{100 \, \text{cm}} \times \frac{1 \, \text{km}}{1000 \, \text{m}} \), so \( 825 \, \text{cm} \times \frac{1 \, \text{m}}{100 \, \text{cm}} \times \frac{1 \, \text{km}}{1000 \, \text{m}}=825\times\frac{1}{100}\times\frac{1}{1000}\, \text{km}=0.00825 \, \text{km} \) (option f)
- \( 2350 \, \text{kg} \times \_\_ = 2350000 \, \text{g} \): \( 1 \, \text{kg}=1000 \, \text{g} \), so \( \frac{1000 \, \text{g}}{1 \, \text{kg}} \) (option e)
- \( 19 \, \text{mL} \times \_\_ = 1.9 \, \text{cL} \): \( 1 \, \text{cL}=10 \, \text{mL} \), so \( \frac{1 \, \text{cL}}{10 \, \text{mL}} \), but option a is \( \frac{1 \, \text{L}}{1000 \, \text{mL}} \)? Wait, no, \( 1 \, \text{cL} = 10 \, \text{mL} \), so \( 19 \, \text{mL} \times \frac{1 \, \text{cL}}{10 \, \text{mL}}=1.9 \, \text{cL} \), but option a is \( \frac{1 \, \text{L}}{1000 \, \text{mL}} \), maybe I made a mistake. Wait, \( 1 \, \text{L}=1000 \, \text{mL} \) and \( 1 \, \text{L} = 100 \, \text{cL} \), so \( 1 \, \text{cL}=\frac{1000}{100}\, \text{mL} = 10 \, \text{mL} \), so \( 19 \, \text{mL}=\frac{19}{10}\, \text{cL}=1.9 \, \text{cL} \), so the conversion factor is \( \frac{1 \, \text{cL}}{10 \, \text{mL}} \), but option a is \( \frac{1 \, \text{L}}{1000 \, \text{mL}} \), maybe the problem has a typo, but according to the given, item 7 is matched with a.
- \( 52 \, \text{km} \times \_\_ = 52000 \, \text{m} \): \( 1 \, \text{km}=1000 \, \text{m} \), so \( \frac{1000 \, \text{m}}{1 \, \text{km}} \) (option k)
- \( 36 \, \text{m} \times \_\_ = 3600 \, \text{cm} \): \( 1 \, \text{m}=100 \, \text{cm} \), so \( \frac{100 \, \text{cm}}{1 \, \text{m}} \) (option i)
- \( 18 \, \text{cm} \times \_\_ = 180 \, \text{mm} \): \( 1 \, \text{cm}=10 \, \text{mm} \), so \( \frac{10 \, \text{mm}}{1 \, \text{cm}} \), but looking at Column B, option j is \( \frac{1 \, \text{m}}{100 \, \text{cm}} \times \frac{1 \, \text{km}}{1000 \, \text{m}} \), no. Wait, maybe \( 1 \, \text{cm}=10 \, \text{mm} \), so the conversion factor is \( \frac{10 \, \text{mm}}{1 \, \text{cm}} \), and in Column B, option j is not, maybe I misread. Wait, the original problem's Column B:
- \( j \): \( \frac{1 \, \text{m}}{100 \, \text{cm}} \times \frac{1 \, \text{km}}{1000 \, \text{m}} \) (for item 5)
- For item 10, let's see: \( 1 \, \text{cm}=10 \, \text{mm} \), so \( 18 \, \text{cm} \times 10 \, \text{mm/cm}=180 \, \text{mm} \), so the conversion factor is \( \frac{10 \, \text{mm}}{1 \, \text{cm}} \), but in Column B, is there an option? Wait, maybe the option is \( j \) is not, maybe the correct option for item 10 is \( j \)? No, \( j \) is for km - m - cm conversion. Wait, maybe I made a mistake. Let's re - check the units:
\( 1 \, \text{cm}=10 \, \text{mm} \), so \( 18 \, \text{cm} \times \frac{10 \, \text{mm}}{1 \, \text{cm}} = 180 \, \text{mm} \). In Column B, the option \( j \) is \( \frac{1 \, \text{m}}{100 \, \text{cm}} \times \frac{1 \, \text{km}}{1000 \, \text{m}} \), no. Wait, maybe the problem has a different set of options. Wait, the user's Column B:
- \( j \): \( \frac{1 \, \text{m}}{100 \, \text{cm}} \times \frac{1 \, \text{km}}{1000 \, \text{m}} \)
- \( k \): \( \frac{1000 \, \text{m}}{1 \, \text{km}} \)
So for item 8: \( 52 \, \text{km} \times \frac{1000 \, \text{m}}{1 \, \text{km}}=52000 \, \text{m} \), so item 8 matches with \( k \).
For item 10: \( 18 \, \text{cm} \times \frac{10 \, \text{mm}}{1 \, \text{cm}} = 180 \, \text{mm} \), but in Column B, if we consider that maybe the conversion is \( \frac{10 \, \text{mm}}{1 \, \text{cm}} \) is not listed, but maybe I made a mistake. Wait, the original problem's Column B has option \( j \) as \( \frac{1 \, \text{m}}{100 \, \text{cm}} \times \frac{1 \, \text{km}}{1000 \, \text{m}} \), no. Wait, maybe the correct option for item 10 is \( j \) is not, maybe the problem has a typo. But according to the given, let's proceed:
Final Matches:
- Item 8: \( k \) ( \( \frac{1000 \, \text{m}}{1 \, \text{km}} \) )
- Item 10: Let's check the units again. \( 1 \, \text{cm} = 10 \, \text{mm} \), so \( 18 \, \text{cm} \times 10 \, \text{mm/cm}=180 \, \text{mm} \). In Column B, the option \( j \) is \( \frac{1 \, \text{m}}{100 \, \text{cm}} \times \frac{1 \, \text{km}}{1000 \, \text{m}} \), no. Wait, maybe the option is \( j \) is for another conversion. Wait, the original problem's Column B:
Looking at the options again:
- \( j \): \( \frac{1 \, \text{m}}{100 \, \text{cm}} \times \frac{1 \, \text{km}}{1000 \, \text{m}} \) (this is for converting cm to km, as in item 5)
- \( k \): \( \frac{1000 \, \text{m}}{1 \, \text{km}} \) (for converting km to m, item 8)
For item 10, since \( 1 \, \text{cm}=10 \, \text{mm} \), the conversion factor is \( \frac{10 \, \text{mm}}{1 \, \text{cm}} \), but if we look at the Column B, maybe the option is \( j \) is not, maybe the problem has a mistake. But according to the given, let's assume that the correct match for item 10 is \( j \) is not, and maybe the intended option is \( j \) is wrong. But based on the units:
\( 18 \, \text{cm} \times \frac{10 \, \text{mm}}{1 \, \text{cm}} = 180 \, \text{mm} \), so the conversion factor is \( \frac{10 \, \text{mm}}{1 \, \text{cm}} \), but in Column B, there is no such option. Wait, maybe I misread the options. Let's re - list Column B:
- a: \( \frac{1 \, \text{L}}{1000 \, \text{mL}} \)
- b: \( \frac{1000 \, \text{mg}}{1 \, \text{g}} \)
- c: \( \frac{1 \, \text{m}}{100 \, \text{cm}} \)
- d: \( \frac{1 \, \text{kL}}{1000 \, \text{L}} \)
- e: \( \frac{1000 \, \text{g}}{1 \, \text{kg}} \)
- f: \( \frac{1 \, \text{m}}{100 \, \text{cm}} \times \frac{1 \, \text{km}}{1000 \, \text{m}} \)
- g: \( \frac{100 \, \text{cg}}{1 \, \text{g}} \)
- h: \( \frac{1 \, \text{g}}{1000 \, \text{mg}} \)
- i: \( \frac{100 \, \text{cm}}{1 \, \text{m}} \)
- j: \( \frac{1 \, \text{m}}{100 \, \text{cm}} \times \frac{1 \, \text{km}}{1000 \, \text{m}} \) (same as f? No, maybe a typo)
- k: \( \frac{1000 \, \text{m}}{1 \, \text{km}} \)
Ah! Wait, \( 1 \, \text{cm}=10 \, \text{mm} \), so \( 18 \, \text{cm} \times \frac{10 \, \text{mm}}{1 \, \text{cm}} = 180 \, \text{mm} \). But in Column B, there is no option with \( \frac{10 \, \text{mm}}{1 \, \text{cm}} \). Maybe the problem intended to