QUESTION IMAGE
Question
for each problem, find the: x and y intercepts, x - coordinates of the critical points, open intervals where the function is increasing and decreasing, x - coordinates of the inflection points, open intervals where the function is concave up and concave down, and relative minima and maxima. using this information, sketch the graph of the function.
- $y =-\frac{x^{3}}{3}+x^{2}$
Step1: Find x - intercepts
Set $y = 0$. So, $-\frac{x^{3}}{3}+x^{2}=0$. Factor out $x^{2}$: $x^{2}(1 - \frac{x}{3})=0$. Then $x = 0$ or $x = 3$.
Step2: Find y - intercepts
Set $x = 0$. Then $y=-\frac{0^{3}}{3}+0^{2}=0$.
Step3: Find the first - derivative
Differentiate $y =-\frac{x^{3}}{3}+x^{2}$ using the power rule. $y'=-x^{2}+2x$.
Step4: Find critical points
Set $y' = 0$. So, $-x^{2}+2x = 0$. Factor out $-x$: $-x(x - 2)=0$. The critical points are $x = 0$ and $x = 2$.
Step5: Determine intervals of increase and decrease
Test intervals $(-\infty,0)$, $(0,2)$ and $(2,\infty)$.
For $x=-1$ in $(-\infty,0)$, $y'=-(-1)^{2}+2(-1)=-3<0$, so the function is decreasing on $(-\infty,0)$.
For $x = 1$ in $(0,2)$, $y'=-1^{2}+2\times1 = 1>0$, so the function is increasing on $(0,2)$.
For $x = 3$ in $(2,\infty)$, $y'=-3^{2}+2\times3=-3<0$, so the function is decreasing on $(2,\infty)$.
Step6: Find the second - derivative
Differentiate $y'=-x^{2}+2x$. $y''=-2x + 2$.
Step7: Find inflection points
Set $y'' = 0$. So, $-2x+2 = 0$, which gives $x = 1$.
Step8: Determine concavity
Test intervals $(-\infty,1)$ and $(1,\infty)$.
For $x = 0$ in $(-\infty,1)$, $y''=-2\times0 + 2=2>0$, so the function is concave up on $(-\infty,1)$.
For $x = 2$ in $(1,\infty)$, $y''=-2\times2+2=-2<0$, so the function is concave down on $(1,\infty)$.
Step9: Find relative minima and maxima
Since the function changes from decreasing to increasing at $x = 0$, $y(0)=0$ is a relative minimum.
Since the function changes from increasing to decreasing at $x = 2$, $y(2)=-\frac{2^{3}}{3}+2^{2}=-\frac{8}{3}+4=\frac{4}{3}$ is a relative maximum.
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- x - intercepts: $x = 0,x = 3$
- y - intercept: $y = 0$
- Critical points: $x = 0,x = 2$
- Intervals of increase: $(0,2)$
- Intervals of decrease: $(-\infty,0)\cup(2,\infty)$
- Inflection point: $x = 1$
- Intervals of concavity: Concave up on $(-\infty,1)$, concave down on $(1,\infty)$
- Relative minimum: At $x = 0,y = 0$
- Relative maximum: At $x = 2,y=\frac{4}{3}$