Question

each of two parents has the genotype blond/red, which consists of the pair of alleles that determine hair color, and each parent contributes one of those alleles to a child. assume that if the child has at least one blond allele, that color will dominate and the childs hair color will be blond. a. list the different possible outcomes. assume that these outcomes are equally likely. b. what is the probability that a child of these parents will have the red/red genotype? c. what is the probability that the child will have blond hair color? a. list the possible outcomes. a. blond/blond, blond/red, red/blond, and red/red b. blond/blond, blond/red, and red/red c. blond/red and red/blond d. blond/blond and red/red

Explanation:

Step1: Analyze possible allele - contributions

Each parent has alleles blond and red. When combining alleles from two parents, we consider all combinations.
The first parent can contribute either blond or red, and for each of these, the second parent can also contribute either blond or red.
The possible combinations are: (blond from parent 1, blond from parent 2), (blond from parent 1, red from parent 2), (red from parent 1, blond from parent 2), (red from parent 1, red from parent 2), which are written as blond/blond, blond/red, red/blond, red/red.

Step2: Calculate probability of red/red genotype

There are a total of 4 possible genotypes (blond/blond, blond/red, red/blond, red/red). Since all outcomes are equally likely, the probability of the red/red genotype is $\frac{1}{4}$ because there is 1 red/red outcome out of 4 total outcomes.

Step3: Calculate probability of blond - hair color

A child has blond - hair color if the genotype is blond/blond, blond/red, or red/blond. There are 3 such genotypes out of 4 total genotypes. So the probability of blond - hair color is $\frac{3}{4}$.

Answer:

a. A. blond/blond, blond/red, red/blond, and red/red
b. $\frac{1}{4}$
c. $\frac{3}{4}$