Question

1. in ▱efgh, find the measure of ∠gfh.

Explanation:

Step1: Recall properties of parallelogram

In parallelogram $EFGH$, $EF\parallel GH$.

Step2: Use alternate - interior angles

$\angle EGH$ and $\angle FHG$ are alternate - interior angles. Since $\angle EGH = 60^{\circ}$, then $\angle FHG=\angle EGH = 60^{\circ}$. In right - triangle $FGH$ (assuming $EF\parallel GH$ and adjacent sides are perpendicular in the context of the problem setup), $\angle GFH = 30^{\circ}$ because in a right - triangle, if one non - right angle is $60^{\circ}$, the other non - right angle is $180^{\circ}-90^{\circ}-60^{\circ}=30^{\circ}$.

Answer:

B. $30^{\circ}$