Question

1. in ▱efgh, find the measure of ∠ghe

60°
120°
30°
90°

Explanation:

Step1: Recall properties of parallelogram

In parallelogram EFGH, opposite - angles are equal and adjacent - angles are supplementary. $\angle EGH = 60^{\circ}$, and $\angle EGH$ and $\angle GHE$ are adjacent angles.

Step2: Use the supplementary - angle property

Since the sum of adjacent angles in a parallelogram is $180^{\circ}$, if $\angle EGH=x = 60^{\circ}$ and $\angle GHE = y$, then $x + y=180^{\circ}$.
So, $y=180^{\circ}-\angle EGH$.
Substitute $\angle EGH = 60^{\circ}$ into the equation: $y = 180 - 60=120^{\circ}$.

Answer:

$120^{\circ}$