Question

energy of motion
a 1 kg hawk flies at a
speed of 12 m/s.
how much kinetic energy
does the hawk have?
remember : $e_k = \frac{1}{2}mv^2$
$e_k = ?$ j

Explanation:

Step1: Identify given values

Mass \( m = 1 \, \text{kg} \), velocity \( v = 12 \, \text{m/s} \), formula \( E_K=\frac{1}{2}mv^2 \).

Step2: Substitute values into formula

Substitute \( m = 1 \) and \( v = 12 \) into \( E_K=\frac{1}{2}mv^2 \):
\( E_K=\frac{1}{2} \times 1 \times (12)^2 \)

Step3: Calculate the result

First, \( 12^2 = 144 \). Then, \( \frac{1}{2} \times 1 \times 144 = 72 \).

Answer:

72