Question

equal to zero.
adratic formula with $a = 1$, $b = 8$, and $c = -40$.
$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$
$x = \frac{-(8) \pm \sqrt{(8)^2 - 4(1)(-40)}}{2(1)}$
$x = \frac{-8 \pm \sqrt{\square}}{2}$

Explanation:

Step1: Calculate the discriminant inside the square root

First, we need to compute the value of \(b^2 - 4ac\) where \(a = 1\), \(b = 8\), and \(c=-40\).
So, \(b^2-4ac=(8)^2 - 4\times(1)\times(-40)\)
\(= 64+160\) (because \(-4\times1\times(-40)=160\))
\(= 224\)

Step2: Substitute the discriminant into the formula

Now we substitute the value of the discriminant into the square root in the quadratic formula. So the expression under the square root is \(224\).

Answer:

\(224\)